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pyrimidines, the backbones would narrow. In both cases,                       A and T are held
                      there would be excessive strain on the covalent bonds in the                  together by two
                                                                                                    hydrogen bonds.
                      sugar–phosphate backbone. The pairing of one purine (with
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                      one ring) and one pyrimidine (with two rings) preserves                 N    H
                      the distance between the backbones along the length of the                    N  H       O     CH 3
                      entire molecule.                                                     N         N      H  N
                            Because they form specific pairs, the bases A and T       Deoxyribose  N                N N

                      are said to be  complementary  , as are the bases G and C.                                O  Deoxyribose
                      The formation of only A–T and G–C base pairs means                   Adenine (A)         Thymine (T)
                      that the paired strands in a double-stranded DNA mole-
                      cule have different base sequences. The strands are paired
                      like this:                                                                    G and C are held
                                                                                                    together by three
                                                                                                    hydrogen bonds.
                                             5’–ATGC–3’                                                          H
                                                                                              N
                                            3’–TACG–5’                                              O        H  N N N
                        where one strand has the base A, the other strand across the       N         N  H      N
                      way has the base T. Likewise, where one strand has a G, the     Deoxyribose  N                N N
                      other has a C. In other words, the paired strands are not                     N  H        O  Deoxyribose
                      identical but complementary. Because of the A–T and G–C                      H
                      base pairing, knowing the base sequence in one strand tells          Guanine (G)         Cytosine (C)
                      you the base sequence in its partner strand.            FIGURE   5.7      Base pairing
                            Why is it that A pairs only with T, and G only with C?

                      FIGURE 5.7   illustrates the answer. The specificity of base     In DNA, the base A pairs with T, and G pairs with C. This pairing results
                                                                              from hydrogen bonds between the two bases. An A–T base pair has
                      pairing is brought about by hydrogen bonds that form    two hydrogen bonds, and a G–C base pair has three hydrogen bonds.
                      between A and T, which have two hydrogen bonds, and
                      between G and C, which have three hydrogen bonds.
                      A hydrogen bond in DNA is formed when an electro negative     Concept Check
                      atom (O or N) in one base shares a hydrogen atom (H)

                                                                                      6.   DNA is shaped like a double helix that resembles a
                      with another electronegative atom in the base across the   spiral staircase.  Describe  which parts of the molecule
                      way. Hydrogen bonds are relatively weak bonds, and can    make up the banisters and which parts make up the
                      be disrupted by high pH or heat. However, added together,   steps of the staircase.
                      millions of these weak bonds along the molecule contribute     7.     Identify  which nucleotides pair with each other in DNA.
                      to the stability of the DNA double helix.




                          5.4  DNA and RNA have                               each RNA strand has directionality, or polarity, determined

                      similarities and differences                            by which end of the chain carries the 5′ phosphate group and
                                                                              which end carries the 3′ hydroxyl group (OOH).
                        In this module, we have focused on the nucleic acid DNA.     A number of important differences distinguish RNA from
                      Like DNA, RNA is a nucleic acid. As a result, it has many   DNA, however. First, the sugar in DNA is deoxyribose, while
                      similarities with DNA. At the same time, there are import-  the sugar in RNA is ribose, shown in    FIGURE 5.8   . The  sugars
                      ant differences between the two molecules, which influence   differ in that ribose has a hydroxyl (OOH) group on the  second
                      both their structure and function. In this section, we will   carbon (designated the 2′ carbon), whereas deoxyribose has
                      take a look at the similarities of DNA and RNA, as well as   a hydrogen atom at this position (hence,  deoxy  ribose, which
                      the differences that distinguish DNA from RNA.          means “minus an oxygen”). These groups are highlighted in
                            DNA and RNA are both nucleic acids. They are poly-  pink in the figure. Hydroxyl groups are reactive functional
                      mers made up of repeating subunits, called nucleotides, which   groups, so the additional hydroxyl group on ribose in part
                      are joined to each other by phosphodiester bonds. Like DNA,   explains why RNA is a less stable molecule than DNA.
                                                                                                      MODULE 5   Nucleic Acids   83

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          08_morrisapbiology1e_11331_Unit1_Mod5_78-91_2pp.indd   83                                                             30/03/21   9:54 AM
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